Ask Question
11 October, 19:47

How much of a sample remains after five half-lives have occurred?

1/5 of the original sample

1/25 of the original sample

1/32 of the original sample

1/64 of the original sample

BOB

+4
Answers (1)
  1. 11 October, 20:16
    0
    1/32 of the original sample

    Explanation:

    We have to use the formula

    N/No = (1/2) ^t/t1/2

    N = amount of radioactive sample left after n number of half lives

    No = original amount of radioactive sample present

    t = time taken for the amount of radioactive samples to reduce to N

    t1/2 = half-life of the radioactive sample

    We have been told that t = five half lives. This implies that t = 5 (t1/2)

    N/No = (1/2) ^5 (t1/2) / t1/2

    Note that the ratio of radioactive samples left after time (t) is given by N/No. Hence;

    N/No = (1/2) ^5

    N/No = 1/32

    Hence the fraction left is 1/32 of the original sample.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How much of a sample remains after five half-lives have occurred? 1/5 of the original sample 1/25 of the original sample 1/32 of the ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers