Ask Question
20 January, 07:38

A chemist prepares a solution of potassium permanganate by measuring out 26. g of potassium permanganate into a 350. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's potassium permanganate solution. Be sure your answer has the correct number of significant digits.

+1
Answers (2)
  1. 20 January, 09:19
    0
    0.471 mol/L

    Explanation:

    First, we'll begin by by calculating the number of mole of KMnO4 in 26g of KMnO4.

    This is illustrated below:

    Molar Mass of KMnO4 = 39 + 55 + (16x4) = 39 + 55 + 64 = 158g/mol

    Mass of KMnO4 from the question = 26g

    Mole of KMnO4 = ?

    Number of mole = Mass/Molar Mass

    Mole of KMnO4 = 26/158 = 0.165mole

    Now we can obtain the concentration of KMnO4 in mol/L as follow:

    Volume of the solution = 350mL = 350/1000 = 0.35L

    Mole of KMnO4 = 0.165mole

    Conc. In mol/L = mole of solute (KMnO4) / volume of solution

    Conc. In mol/L = 0.165mol/0.35

    conc. in mol/L = 0.471mol/L
  2. 20 January, 10:10
    0
    The concentration of this potassium permanganate solution is 0.470 mol/L or 0.470 M

    Explanation:

    Step 1: data given

    Mass of potassium permanganate = 26.0 grams

    Molar mass of potassium permanganate = 158.034 g/mol

    Volume = 350 mL = 0.350 L

    Step 2: Calculate moles potassium permanganate

    Moles KMnO4 = mass KMnO4 / molar mass KMnO4

    Moles KMnO4 = 26.0 grams / 158.034 g/mol

    Moles KMnO4 = 0.1645 moles

    Step 3: Calculate concentration of KMnO4 solution

    Concentration KMnO4 = moles KMnO4 / volume

    Concentration KMnO4 = 0.1645 moles / 0.350 L

    Concentration KMnO4 = 0.470 M

    The concentration of this potassium permanganate solution is 0.470 mol/L or 0.470 M
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A chemist prepares a solution of potassium permanganate by measuring out 26. g of potassium permanganate into a 350. mL volumetric flask ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers