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24 March, 20:43

Indicate the coordination number for the central metal atom in each of the following coordination compounds:

(a) [Pt (H2O) 2Br2]

(b) [Pt (NH3) (py) (Cl) (Br) ] (py = pyridine, C5H5N)

(c) [Zn (NH3) 2Cl2]

(d) [Zn (NH3) (py) (Cl) (Br) ]

(e) [Ni (H2O) 4Cl2]

(f) [Fe (en) 2 (CN) 2] + (en = ethylenediamine, C2H8N2)

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  1. 24 March, 22:51
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    Answer: A. 4, since all 4 ligands (2 H2O&2Br) are monodentate hence 4x1=4

    B. 4, (4x1=4)

    C. 4 (4x1=4)

    D. 4 (4x1=4)

    E. 6 (6x1=6)

    F. 6 (2 (2) + 2 (1) = 4+2=6) en is bidentate ligand

    Explanation:

    Coordination number is equal to number of ligands surrounded the metal atom.

    Coordination number = No of ligands X denticity

    Denticity is nothing but nature of ligands like mono, bi dentate, or tetrads rate etc.
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