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10 March, 09:17

How many representative particles are in 1.45 g of a molecular compound with a molar mass of 237 g?

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  1. 10 March, 12:56
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    Answer: 3.68 x 10^21 particles

    Explanation:

    Based on Avogadro's law:

    1 mole of any substance has 6.02 x 10^23 atoms

    Since 1 mole is the same as molar mass of a substance

    237 g = 6.02 x 10^23 atoms

    1.45g = Z atoms

    To get the value of Z, cross multiply:

    (Z atoms x 237g) = (6.02 x 10^23 atoms x 1.45g)

    237Z = 8.729 x 10^23

    Z = (8.729 x 10^23 / 237)

    Z = 3.68 x 10^21

    Thus, there are 3.68 x 10^21 representative particles in 1.45 g of the molecular compound.
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