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28 November, 03:27

How many grams of caf2 are present in 1.25 l of a 0.15 m solution of caf2

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  1. 28 November, 07:12
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    9.36g of CaF2 is presnt in the solution.

    Explanation:

    CaF2 molar concentration is 0.15mol in 1.25l of solution.

    1. Convert this to the standard concentration in mol/dm3:

    1dm3 = 1 L

    0.15mol = 1.25 dm3

    x = 1 dm3

    0.15 = 1.25 x

    x = 0.15/1.25

    x = 0.12 mol/dm3

    2. Calculate the relative molecular mass of CaF2

    Ca = 40, F = 19

    RMM = 40 + 19 * 2

    RMM = 40 + 38

    RMM = 78g/mol

    3. Calculate the concentration in g/dm3

    conc. in mol/dm3 = conc in g/dm3 / RMM

    conc in g/dm3 = conc in mol/dm3 * RMM

    = 0.12mol/dm3 * 78g/mol

    = 9.36 g/dm3

    So therefore, 9.36g of CaF2 is presnt in the solution.
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