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13 December, 06:38

How many grams of O2 are needed to react with 13.6 g of NH3

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  1. 13 December, 09:46
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    Mass = 32 g

    Explanation:

    Given dа ta:

    Mass of O₂ needed = ?

    Mass of NH₃ react = 13.6 g

    Solution:

    Chemical equation:

    4NH₃ + 5O₂ → 4NO + 6H₂O

    Number of moles of ammonia:

    Number of moles = mass / molar mass

    Number of moles = 13.6 g / 17 g/mol

    Number of moles = 0.8 mol

    Now we will compare the moles of ammonia and oxygen from balance chemical equation.

    NH₃ : O₂

    4 : 5

    0.8 : 5/4*0.8 = 1

    Mass of oxygen:

    Mass = number of moles * molar mass

    Mass = 1 mol * 32 g/mol

    Mass = 32 g
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