Seven moles of Argon gas are at a presseure of 2.90 atm, and the temperature is 50c. What is the volume of the gas?

At s. t. p, the volume of a gas = 22.4dm³

Talking the problem,

At 1atm, 273K the volume = 7 moles * 22.4dm³/mol

At 323K, 2.90atm, volume = ?

The combined gas equation

P1v1/T1=P2v2/T2

P1=1atm

P2=2.9atm

T1=273K

T2=323K

V1=156.8dm³

Therefore,

1*156.8dm³/273=2.9atm*V2/323

V2 = (156.8dm³*323K) / (273K*2.9atm)

= 64dm³