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28 August, 03:15

Consider the following balanced reaction between hydrogen and nitrogen to form ammonia:

3H2 (g) + N2 (g) →2NH3 (g)

How many moles of NH3 can be produced from 19.0 mol of H2 and excess N2?

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  1. 28 August, 07:05
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    Three moles of H2 produce 2 moles of NH3. Since the reactinng ratios are constant, then the ratio of hydrogen consumed:ammonia is 3:2

    Mathematically, 3 Mol H2=2mol NH3

    19 Molly H2=?

    Cross-multiplying gives;

    (19*2) / 3=12.67 moles
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