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15 October, 17:54

The reaction A (g) ⇌ 2 B (g) A (g) ⇌ 2 B (g) has an equilibrium constant of K = 0.010 K = 0.010. What is the equilibrium constant for the reaction B (g) ⇌ 1 2 A (g) ?

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  1. 15 October, 20:55
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    K = 10

    Explanation:

    Using Hess's law, it is possible to obtain the equilibrium constant, K, of a reaction using K of similar reactions. For example:

    If A ⇄ B K = X

    B ⇄ A K = 1/X

    2A ⇄ 2B K = X².

    Thus, if A (g) ⇄ 2B (g) K = 0.010

    2B (g) ⇄ A (g) K = 1 / 0.010; K = 100

    B (g) ⇄ A (g) K = √100 = 10

    K = 10
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