The density of an unknown crystal is 2.65 g/mol. What will the volume read if a 4.46 g sample is added to a graduated cylinder containing 25.0 ml of water?

The density of crystal is 2.65 g / mL

we know that

Density = Mass / Volume

So volume occupied = Mass / density

Mass of crystal = 4.46 g

So volume occupied by crystal = 4.46 / 2.65 = 1.68 mL

As the graduated cylinder contains water upto 25.0 mL

So if we immerse the crystal in that cylinder the water level will rise to 25+1.68 = 26.68mL

so the new read will be 26. 68 mL