Calculate the cell potential for the galvanic cell in which the reaction Fe (s) + Au 3 + (aq) - ⇀ ↽ - Fe 3 + (aq) + Au (s) occurs at 25 ∘ C, given that [ Fe 3 + ] = 0.00150 M and [ Au 3 + ] = 0.797 M.

Question

Chemistry

Cristopher Compton

Today, 04:16

Calculate the cell potential for the galvanic cell in which the reaction Fe (s) + Au 3 + (aq) - ⇀ ↽ - Fe 3 + (aq) + Au (s) occurs at 25 ∘ C, given that [ Fe 3 + ] = 0.00150 M and [ Au 3 + ] = 0.797 M.

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Answers (1)

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Baylee Curtis · Answer 1

0.79 V

Explanation:

From Nernst equation:

E = E° - 0.0592/n log [red]/[ox]

Number of electrons transferred=3

[Red]=0.797 M.

[Ox] = 0.00150 M

First we obtain E° = 0.80 - (-0.04) = 0.84 V

E = 0.84 - 0.0592/3 log [0.797]/[0.00150]

E = 0.84-0.05

E = 0.79 V