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30 June, 12:06

A binding protein binds to a ligand l with a kd of 400 nm what is the concentration of ligand when y is 0.25

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  1. 30 June, 12:56
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    The answer is 7600 nm.

    Explanation:

    As, Y = 0.25 = [ L : (400 + (L) ]

    0.95 x 400 + 0.25 [ L] = [ L ]

    380.25 = [ L ] - 0.95 [ L ]

    = 0.05 [L]

    [L] = 380 : 0.05 = 7600nm
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