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25 May, 04:46

What is the temperature of 16.45 moles of methane gas in a 4.95 L container at 4.68 atm?

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  1. 25 May, 05:44
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    You have to use the ideal gas law of PV=nRT.

    In this case, you just have to plug in the given variables.

    P (pressure) = 4.68 atm

    V (volume) = 4.95 L

    n (number of moles) = 16.45

    R (gas constant) =.0821

    T (temperature) is what youre trying to solve so:

    (4.68) * (4.95) = (16.45) * (.0821) * T

    To get T by itself, divide both sides by (16.45) * (0.821) to get T of 17.15.
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