Which of the following laboratory procedures best illustrates the law of conservation of mass?

Calculating the number of atoms in 11 g of Na

Using 250 g of impure Cu to obtain 200 g of pure Cu

Heating 32 g of S and 56 g of Fe to produce 88 g of FeS and unused reactants

Burning 2.4 g of Mg in an open crucible to produce 2 g of MgO and unused reactants

Answer: Option (c) is the correct answer.

Explanation:

According to law of conservation of mass, in an isolated system mass cannot be created or destroyed as it can be transformed from one form to another.

For example, heating 32 g of S and 56 g of Fe to produce 88 g of FeS and unused reactants.

So, total mass of reactants is 32 g + 56 g = 88 g. And, total mass of product formed is also 88 g.

Therefore, mass is neither destroyed nor created as it simply transformed from one from form to another.

Thus, we can conclude that heating 32 g of S and 56 g of Fe to produce 88 g of FeS and unused reactants, best illustrates the law of conservation of mass.

it would be heating of 32g of s and 56g of Fe to produce 88g of FeS and unused reactants