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29 August, 18:10

How many milliliters of 0.10 m pb (no3) 2 are required to react with 75 ml of 0.20 m nai? pb (no3) 2 + 2 nai - -> pbi2 + 2 nano3?

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  1. 29 August, 19:33
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    The Ml of 0.10 Pb (NO3) 2 that are required to react with 75 Ml of 0.20M Nai is 75 ml

    calculation

    Pb (NO3) 2 + 2Nai → Pbi2 + 2NaNo3

    find the number of moles of Nai used

    moles = molarity x volume in liters

    volume in liters = 75/1000=0.075 moles

    mole = 0.20 x0.075 = 0.015 moles

    by use of mole ratio between Pb (NO3) 2 to Nai which is 1 : 2 the moles of Pb (NO3) 2 = 0.015 x1/2 = 7.5 x10^-3 moles

    volume (ml)) = moles/molarity x 1000

    =volume = (7.5 x10^-3) / 0.10 = 75 Ml
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