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3 January, 13:02

The air inside a flexible 3.5L container has a pressure of 115Kpa. What should the volume of the container be increased to in the order to decrease the pressure to 625 tore?

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  1. 3 January, 14:06
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    V₂ = 4.82 L

    Explanation:

    Given dа ta:

    Initial volume of gas = 3.5 L

    Initial pressure = 115 Kpa

    Final volume = ?

    Final Pressure = 625 torr

    Solution:

    Final Pressure = 625 torr (625/760 = 0.82 atm)

    Initial pressure = 115 Kpa (115/101 = 1.13 atm)

    The given problem will be solved through the Boly's law,

    "The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

    Mathematical expression:

    P₁V₁ = P₂V₂

    P₁ = Initial pressure

    V₁ = initial volume

    P₂ = final pressure

    V₂ = final volume

    Now we will put the values in formula,

    P₁V₁ = P₂V₂

    1.13 atm * 3.5 L = 0.82 atm * V₂

    V₂ = 3.955 atm. L/0.82 atm

    V₂ = 4.82 L
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