How many moles of potassium oxide will be formed when 1.52 moles of potassium reacts with oxygen according to the following equation:

4K + O2 - > 2K2O

the balanced equation for formation of potassium oxide is as follows

4K + O₂ - -> 2K₂O

molar ratio of K to K₂O is 4:2

when 4 mol of potassium reacts, 2 mol of potassium oxide is formed

when 4 mol of K reacts - 2 mol of K₂O

when 1.52 mol of K reacts - 2/4 x 1.52 = 0.76 mol of K₂O

0.76 mol of K₂O is formed

0.76 mol.

Explanation:

From the balanced equation: 4K + O₂ → 2K₂O, It is clear that 4.0 moles of K react with 1.0 mole of oxygen to produce 2.0 moles of K₂O. We can use cross multiplication to get the no. of moles of potassium oxide will be formed when 1.52 moles of potassium reacts with oxygen:

4.0 moles of K will produce → 2.0 moles of K₂O.

1.52 moles of K will produce →? moles of K₂O.

∴ The no. of moles of potassium oxide will be formed when 1.52 moles of potassium reacts with oxygen = (1.52 mol) (2.0 mol) / (4.0 mol) = 0.76 mol.