Ask Question
4 December, 15:49

12 liters of ammonia (NH3) weighs how much at room temperature and pressure (293 K and 100 kPa) ?

• O A. 12 grams

• O B. 0.5 grams

• O C. 17 grams

• O D. 8.5 grams

+4
Answers (1)
  1. 4 December, 19:02
    0
    Option D) 8.5 grams

    Explanation:

    1) dа ta:

    a) V = 12 liter

    b) T = 293 K

    c) p = 100 kPa

    d) mass = ?

    2) Formulae:

    a) Ideal gas equation: pV = nRT

    b) molar mass = mass in grams / number of moles

    3) Solution:

    a) Calculate the number of moles of ammonia, n:

    pV = nRT ⇒ n = RT / (pV)

    R = universal constant of gases = 8.3145 liter-kPa / mol-K

    n = 100 kPa * 12 liter / (293 K * 8.3145 liter-kPa/mol-K) = 0.493 mol

    b) Convert moles to grams:

    Molar mass of NH₃ = 14.007 g/mol + 3*1.008 g/mol = 17.03 g/mol

    mass = 0.493 mol * 17.03 g/mol = 8.4 g

    Thus, the answer is the option D. 8.5 grams.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “12 liters of ammonia (NH3) weighs how much at room temperature and pressure (293 K and 100 kPa) ? • O A. 12 grams • O B. 0.5 grams • O C. ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers