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19 June, 13:02

A solution has pOH 5.9

A) What is the [OH-]?

B) What is the [H3O+]?

C) Is this acidic, alkaline, or neutral?

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Answers (2)
  1. 19 June, 13:28
    0
    The answer to your question is below

    Explanation:

    Data

    pOH = 5.9

    a) [OH⁻] = ?

    pOH measures the [OH⁻]

    Formula

    pOH = - log[OH⁻]

    -Substitution

    5.9 = - log[OH⁻]

    [OH⁻] = antilog (-5.9)

    -Result

    [OH⁻] = 1.26 x 10⁻⁶ M

    b) [H₃O⁺]

    pH + pOH = 14

    -Solve for pH

    pH = 14 - pOH

    -Substitution

    pH = 14 - 5.9

    -Result

    pH = 8.1

    -Calculate [H₃O⁺]

    pH = - log[H₃O⁺]

    -Substitution

    8.1 = - log[H₃O⁺]

    [H₃O⁺] = antilog (-8.1)

    -Result

    [H₃O⁺] = 7.9 x 10⁻⁹ M

    c) This solution is alkaline because the pH is higher than 7.
  2. 19 June, 14:24
    0
    The answer is A

    A. Poh 5.9
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