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2 September, 00:16

A balloon has 18.9 moles of hydrogen gas at a volume of 428 L. What would the volume of the gas be if the balloon had 14.0 moles of hydrogen gas left after 1 day?

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  1. 2 September, 03:24
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    V₂ = 317 L

    Explanation:

    Given dа ta:

    Initial number of moles of hydrogen = 18.9 mol

    Initial volume of gas = 428 L

    Final volume = ?

    Final number of moles = 14.0 mol

    Solution:

    According to the Avogadro law,

    Number of moles of gas is directly proportional to the volume of gas at constant temperature and pressure.

    Mathematical expression:

    V₁/n₁ = V₂/n₂

    V₁ = Initial Volume of balloon

    n₁ = initial number of moles

    V₂ = Final volume of balloon

    n₂ = Final number of moles

    Now we will put the values.

    428 L / 18.9 mol = V₂ / 14 mol

    V₂ = 428 L * 14 mol / 18.9 mol

    V₂ = 5992 L / 18.9

    V₂ = 317 L
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