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17 July, 19:56

What is the molarity of Cl - in each solution?

a. 0.210 M NaCl

b. 0.160 M SrCl2

c. 0.110M AlCl3

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  1. 17 July, 20:21
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    a. 0.210 M.

    b. 0.32 M.

    c. 0.33 M.

    Explanation:

    a. 0.210 M NaCl:

    NaCl is ionized in the solution according to:

    NaCl → Na⁺ + Cl⁻.

    It is ionized to give 1 mole of Na⁺ and 1 mole of Cl⁻.

    ∴ [Cl⁻] = 0.210 M.

    b. 0.160 M SrCl₂:

    SrCl₂ is ionized in the solution according to:

    SrCl₂ → Sr²⁺ + 2Cl⁻.

    It is ionized to give 1 mole of Sr²⁺ and 2 mole of Cl⁻.

    ∴ [Cl⁻] = 2 x (0.160) = 0.32 M.

    c. 0.110M AlCl₃:

    AlCl₃ is ionized in the solution according to:

    AlCl₃ → Al³⁺ + 3Cl⁻.

    It is ionized to give 1 mole of Al³⁺ and 3 mole of Cl⁻.

    ∴ [Cl⁻] = 3 x (0.110) = 0.33 M.
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