What is the molarity of Cl - in each solution?

a. 0.210 M NaCl

b. 0.160 M SrCl2

c. 0.110M AlCl3

a. 0.210 M.

b. 0.32 M.

c. 0.33 M.

Explanation:

a. 0.210 M NaCl:

NaCl is ionized in the solution according to:

NaCl → Na⁺ + Cl⁻.

It is ionized to give 1 mole of Na⁺ and 1 mole of Cl⁻.

∴ [Cl⁻] = 0.210 M.

b. 0.160 M SrCl₂:

SrCl₂ is ionized in the solution according to:

SrCl₂ → Sr²⁺ + 2Cl⁻.

It is ionized to give 1 mole of Sr²⁺ and 2 mole of Cl⁻.

∴ [Cl⁻] = 2 x (0.160) = 0.32 M.

c. 0.110M AlCl₃:

AlCl₃ is ionized in the solution according to:

AlCl₃ → Al³⁺ + 3Cl⁻.

It is ionized to give 1 mole of Al³⁺ and 3 mole of Cl⁻.

∴ [Cl⁻] = 3 x (0.110) = 0.33 M.