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30 March, 04:00

A 2.10 L vessel contains 4.65 mol of nitrous oxide (N2O) at 3.82 atm. What will be the pressure of this gas in a container that's half the size?

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  1. 30 March, 06:22
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    The answer to your question is 7.64 atm

    Explanation:

    Data

    Volume 1 = V1 = 2.1 l

    moles = 4.65

    Pressure 1 = P1 = 3.82 atm

    Volume 2 = Volume 1/2

    Pressure 2 = ?

    Process

    1. - Calculate the new volume

    Volume 2 = 2.10/2

    Volume 2 = 1.05 l

    2. - Use Boyle's law to find the Pressure

    P1V1 = P2V2

    -Solve for P2

    P2 = P1V1 / V2

    -Substitution

    P2 = (3.82) (2.1) / 1.05

    -Simplification

    P2 = 8.022/1.05

    -Result

    P2 = 7.64 atm
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