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3 February, 18:54

What is the pOH of a 0.00037 M solution of barium hydroxide

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  1. 3 February, 22:40
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    Answer: pOH = 3.13

    Ba (OH) 2 is a very basic substance. The general formula for pOH is - log (OH)

    Barium Hydroxide produces 2 moles of OH for every mole of Ba (OH) 2 present in the solution.

    0.00037 M = 3.7 * 10^-4 Ba (OH) 2 will produce 2 * 0.00037 M of OH-

    OH - = 2 * 0.00037 = 0.00074

    pOH = - log (0.00074) = 3.13
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