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27 April, 14:02

A rigid canister holds 50.0 L of helium gas at 32.0°C and 49.9 kPa. The gas is cooled until the pressure reaches 14.2 kPa. What is the Kelvin temperature of the helium?

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  1. 27 April, 14:44
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    Answer:-

    86.794 K

    Explanation:-

    Initial temperature T 1 = 32 C + 273 = 305 K

    Initial Pressure P 1 = 49.9 KPa

    New Pressure P 2 = 14.2 KPa

    The Volume remains same since it is rigid.

    ∴V 1 = V 2 = 50.0 L

    Using the relation

    P 1 V 1 / T1 = P 2 V 2 / T 2

    New temperature T 2 = P 2 V 2 T 1 / (P 1 V 1)

    = 14.2 KPa x 50.0 L x 305 K / (49.9 KPa x 50.0 L)

    = 86.794 K
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