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Chemistry
Tori Horton
3 February, 16:16
How many atoms are there in 43.9g of Na?
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Keenan Mueller
3 February, 18:17
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(43.9g) / (22.99g/mol) = 1.91mol Na
(1.91mol) x (Avogadro number)
= 1.15x10^24 atoms
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