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5 February, 14:28

In the reaction MgCl2 + 2KOH Mg (OH) 2 + 2KCI, if 3 moles MgCh are added to 4 moles KOH, what determines how much Mg (OH) 2 is made?

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  1. 5 February, 17:31
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    Answer:-

    KOH determines how much Mg (OH) 2 is made.

    2 mol of Mg (OH) 2 formed

    Explanation:-

    The balanced equation is

    MgCl2 + 2KOH - -> Mg (OH) 2 + 2KCI,

    From seeing the coefficients we notice

    2 mol of KOH reacts with 1 mol of MgCl2

    4 mol of KOH reacts with 1 x 4 / 2 = 2 mol of MgCl2

    3 moles of MgCl2 was added but only 2 mol react.

    So we see there is excess MgCl2.

    Hence KOH is the limiting reactant.

    So KOH determines how much Mg (OH) 2 is made.

    We see from the balanced chemical equation,

    2 mol of KOH gives 1 mol of Mg (OH) 2.

    4 mol of KOH will give 1 x 4 / 2 = 2 mol of Mg (OH) 2.
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