How many moles of AgCl2 are in 5.78x1024 molecules of AgCl2?

a) 3.48x1048 moles AgCl2

b) 1375.87 moles AgCl2

c) 0.07 moles AgCl2

d) 9.60 moles AgCl2

Question

Chemistry

Martin Eaton

17 February, 05:31

How many moles of AgCl2 are in 5.78x1024 molecules of AgCl2?

a) 3.48x1048 moles AgCl2

b) 1375.87 moles AgCl2

c) 0.07 moles AgCl2

d) 9.60 moles AgCl2

+5

Answers (1)

Know the Answer?

Janet Ramsey · Answer 1

9.6 mol AgCl2

Explanation:

You have to use Avogadro's number: 6.023 x 10^23

5.78 x 10^24 molecules (1 mol AgCl2 / 6.023 x 10^23 molecules) = 9.6 mol AgCl2

How many moles of AgCl2 are in 5.78x1024 molecules of AgCl2?a) 3.48x1048 moles AgCl2b) 1375.87 moles AgCl2c) 0.07 moles AgCl2d) 9.60 moles AgCl2

How many moles of AgCl2 are in 5.78x1024 molecules of AgCl2?

a) 3.48x1048 moles AgCl2

b) 1375.87 moles AgCl2

c) 0.07 moles AgCl2

d) 9.60 moles AgCl2