What is the empirical formula of a compound that is 14 g calcium, 11g oxygen, and 0.7 g hydrogen

CaO2H2

convert to moles, divide all by smallest mole mass, multiply til whole

14 g Ca : 40.08 =.35 mol

11 g O : 16 =.69 mol

.7 g H : 1.008 =.69 mol

.35 :.35 = 1

.69 :.35 = 2

.69 :.35 = 2

CaO2H2