If 25.0 moles of gasohol (C2H60) burns this way, how many moles of oxygen are

needed?

C2H60 + 3 O2 - -> 2 CO2 + 3 H20

a) 75.0 moles

b) 37.5 moles

c) 16.7 moles

d) 8.3 moles

Question

Shepherd

14 April, 09:22

+1

Answers (1)

Know the Answer?

Alyvia · Answer 1

a. 75 mol O2

Explanation:

1 mol C2H6O - > 3 mol O2

25 mol C2H6O - > x

x = (25 mol C2H6O * 3 mol O2) / 1 mol C2H6O

x = 75 mol O2

If 25.0 moles of gasohol (C2H60) burns this way, how many moles of oxygen areneeded?C2H60 + 3 O2 - -> 2 CO2 + 3 H20a) 75.0 molesb) 37.5 molesc) 16.7 molesd) 8.3 moles