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19 March, 10:05

A solution was prepared by mixing 0.5000 m hno2 with 0.380 m no2-. ka = 4.58 x 10-4. calculate the ph of the solution. show work.

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  1. 19 March, 11:45
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    pH of buffer can be calculated as:

    pH=pKa+log[salt]/[Acid]

    As ka = 4.58 x 10-4

    Concentration of [Salt] that is NO2 (-1) = 0.380M

    Concentration of [Acid] that is HNO2=0.500M

    So, pH = - log (4.58*10^-4) + log ((0.380) / 0.500))

    =3.21

    So pH of solution will be 3.21
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