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25 January, 19:54

74.5 g of KCl was dissolved in 1000. mL of water. What is the

molality of the solution? (Molar mass of KCI = 74.5 g/mol)

m.

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Answers (1)
  1. 25 January, 22:22
    0
    Answer = 10M

    Molarity=n/v

    n=m/mm, 74.5/74.5=1mole

    1000ml = 1L

    M=n/v, 1/1=1M
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