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23 October, 20:06

What mass of sodium chloride is needed to prepare 200 ml of a 0.1 M solution

A. 0.232 grams

B. 292 grams

C. 1.17 grams

D. 117 grams

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Answers (2)
  1. 23 October, 23:22
    0
    C. 1.17 grams

    Explanation:

    The molarity is the no. of moles of solute in a 1.0 L of the solution.

    M = (mass/molar mass) solute x (1000 / V)

    M = 0.1 M, mass = ? g, molar mass of NaCl = 58.44 g/mol, V = 200.0 mL.

    ∴ mass of NaCl = (M) (molar mass) (V) / 1000 = (0.1 M) (58.44 g/mol) (200.0 mL) / 1000 = 1.168 g ≅ 1.17 g.
  2. 23 October, 23:31
    0
    The right choice is (C) 1.17 grams

    Explanation:

    As we know

    c = n/V

    n = c * V

    n = m/M

    m = c * V * M

    m = 0.1mol/L * 0.2 L * 58.44 g/mol

    m = 1.1688 g ≈ 1.17 g

    So the mass of NaCl needed will be 1.17 grams
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