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11 February, 14:10

Use Boyle's, Charles's, or Gay-Lussac's law to calculate the missing value in each of the following.

(a) V1 = 2.0 L, P1 = 0.62 atm, V2 = 1.0 L, P2 = ?

atm

(b) V1 = 230 mL, T1 = ?, V2 = 400. mL, T2 = 298 K

K

(c) V1 = 0.55 L, P1 = 740 mm Hg, V2 = 0.84 L, P2 = ?

mm Hg Use Boyle's, Charles's, or Gay-Lussac's law to calculate the missing value in each of the following.

(a) V1 = 2.0 L, P1 = 0.62 atm, V2 = 1.0 L, P2 = ?

atm

(b) V1 = 230 mL, T1 = ?, V2 = 400. mL, T2 = 298 K

K

(c) V1 = 0.55 L, P1 = 740 mm Hg, V2 = 0.84 L, P2 = ?

mm Hg

+3
Answers (1)
  1. 11 February, 17:04
    0
    The missing value is found using the Boyle's Law and P2 = 1.24 atm

    The missing value is found using the Charles 's Law and T1 = 171.35

    Explanation:

    Given data

    1. Volume and pressure is given

    Based on the data, the volume and pressure is given it requires the Boyle's Law

    Boyle's Law:

    P1 V1 = P2V2

    Given data

    V1 = 2.0 L, P1 = 0.62 atm, V2 = 1.0 L, P2 = ?

    (0.62 atm) (2.0L) = P2 (1. OL)

    Dividing both the sides by 1.0L

    we get P2 = 1.24 atm

    The missing value is found using the Boyle's Law and P2 = 1.24 atm

    2. A volume and temperature is given:

    Charles Law:

    V1 / T1 = V2 / T2

    Given data

    V1 = 230 mL, T1 = ?, V2 = 400. mL, T2 = 298 K

    230 ml / T1 = 400 ml / 298 K

    T1 * 400 ml = 68450 ml * K

    T1 = 171.35

    The missing value is found using the Charles 's Law and T1 = 171.35
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