Use Boyle's, Charles's, or Gay-Lussac's law to calculate the missing value in each of the following.

(a) V1 = 2.0 L, P1 = 0.62 atm, V2 = 1.0 L, P2 = ?

atm

(b) V1 = 230 mL, T1 = ?, V2 = 400. mL, T2 = 298 K

K

(c) V1 = 0.55 L, P1 = 740 mm Hg, V2 = 0.84 L, P2 = ?

mm Hg Use Boyle's, Charles's, or Gay-Lussac's law to calculate the missing value in each of the following.

(a) V1 = 2.0 L, P1 = 0.62 atm, V2 = 1.0 L, P2 = ?

atm

(b) V1 = 230 mL, T1 = ?, V2 = 400. mL, T2 = 298 K

K

(c) V1 = 0.55 L, P1 = 740 mm Hg, V2 = 0.84 L, P2 = ?

mm Hg

The missing value is found using the Boyle's Law and P2 = 1.24 atm

The missing value is found using the Charles 's Law and T1 = 171.35

Explanation:

Given data

1. Volume and pressure is given

Based on the data, the volume and pressure is given it requires the Boyle's Law

Boyle's Law:

P1 V1 = P2V2

Given data

V1 = 2.0 L, P1 = 0.62 atm, V2 = 1.0 L, P2 = ?

(0.62 atm) (2.0L) = P2 (1. OL)

Dividing both the sides by 1.0L

we get P2 = 1.24 atm

The missing value is found using the Boyle's Law and P2 = 1.24 atm

2. A volume and temperature is given:

Charles Law:

V1 / T1 = V2 / T2

Given data

V1 = 230 mL, T1 = ?, V2 = 400. mL, T2 = 298 K

230 ml / T1 = 400 ml / 298 K

T1 * 400 ml = 68450 ml * K

T1 = 171.35

The missing value is found using the Charles 's Law and T1 = 171.35