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31 October, 14:15

Suppose that the pressure of 0.66 L of gas is 424.9 mm Hg when the temperature is 261.2 K. At what temperature is the volume 7.63 L and the pressure 872.15 mm Hg?

Select one:

a. 6200

b. 1.24e4

c. 3010

d. 11.0

+4
Answers (2)
  1. 31 October, 16:23
    0
    Option a. 6200 K

    Explanation:

    1) dа ta:

    V₁ = 0.66 liter P₁ = 42.9 mmHg T = 261.2 K

    T₂ = ? V₂ = 7.63 liter P₂ = 872.15 mmHg

    2) Formula:

    Combined law of gases:

    P₁ V₁ / T₁ = P₂ V₂ / T₂

    3) Solution:

    Solve for T₂:

    T₂ = P₂ V₂ T₁ / (P₁ V₁)

    Substitute:

    T₂ = 872.15 mmHg * 7.63 liter * 261.2 K / (424.9 mmHg * 0.66 liter)

    T₂ = 6198 K

    Rounding to 2 significant figures, that is 6200 K, which is the first choice.
  2. 31 October, 16:30
    0
    I believe it's a. 6200
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