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9 February, 19:23

A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm, what is the new volume of the balloon in the hot room? 2.19 L 3.33 L 3.68 L 5.60 L

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  1. 9 February, 21:26
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    Answer:The answer is C on edge!
  2. 9 February, 21:45
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    C. 3.68

    Explanation:

    V1 / T1 = V2 / T2

    3.50 / (25+273) = V2 / (40+273)

    3.50 (40+273) / (25+273) = V2

    V2 = 3.676 3.676=3.68
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