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4 October, 21:36

How many moles of aluminum oxide would form if 12.5 moles of aluminum burned

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  1. 4 October, 23:15
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    Al + O2 - > Al2O3

    Balance it:

    2Al + 3O2 - > 2Al2O3

    So you need 2 Al and 3 O2 to make 2 Al2O3 (aluminum oxide).

    I'm going to assume you have all the O2 you need.

    Since 2 mols of Al is needed to make 2 mols of the product, it's a 1:1 ratio. You get as much aluminum oxide for as much aluminum you burn.

    So 12.5 mols if there is not a lack of the O2.
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