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5 September, 02:22

How many moles of P4 would you need to produce 34 g of PH3?

P4 (s) + 6 H2 (g) → 4 PH3 (g)

0.25 mol

0.5 mol

1 mol

4 mol

0
Answers (1)
  1. 5 September, 04:19
    0
    Molecular weight of P (Phosphorous) = 30.97g/mol

    Hydrogen is just 1 g/mol.

    How many moles is 34g of PH3?

    Get the weight of PH3 (30.97 + (3X1)) = 33.97g/mol

    So 34g/33.97g/mol = 1.0009 moles.

    I bet for this problem it's easier to round this to 1.

    If you look at just the moles in the equation:

    P4 (s) + 6 H2 (g) → 4 PH3 (g)

    OR

    1 + 6 → 4

    If 1 (P4) gives us 4 (PH3), what gives us 1 (PH3) ?

    1/4 = x/1

    solve for x
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