How many grams of perchloric acid should be dissolved in 8500mL of water to make a solution with pH 3.3

0.427 g HClO4

Explanation:

[H+] = 10^-3.3 = 5.01 x 10^-4 M

8500 mL=8.5 L

M = mol solute / L solution

mol solute = M * L solution

mol solute = (5.01 x 10^-4 M * 8.5 L)

mol solute = 4.26 x 10^3 mol HClO4

1 mol HClO4 - > 100. 4 g

4.26 x 10^3 mol HClO4 - > x

x=0.427 g HClO4