Ask Question
15 November, 05:15

How many liters of water can be boiled by burning 1 kg of propane?

Round your answer to the nearest whole number.

+2
Answers (1)
  1. 15 November, 08:43
    0
    2037 L

    Explanation:

    Step 1:

    The balanced equation for the reaction involving the burning of propane. This is given below:

    C3H8 + 5O2 - > 3CO2 + 4H2O

    Step 2:

    Determination of the number of mole in 1kg of propane (C3H8).

    Mass of C3H8 = 1kg = 1000g

    Molar Mass of C3H8 = (3x12) + (8x1) = 36 + 8 = 44g/mol

    Number of mole = Mass/Molar Mass

    Number of mole of C3H8 = 1000/44

    Number of mole of C3H8 = 22.73 moles

    Step 3:

    Determination of the number of mole of water produced by burning 1 kg of propane (C3H8). This is illustrated below:

    From the balanced equation above,

    1 mole of C3H8 boiled 4 moles of H2O.

    Therefore, 22.73 moles of C3H8 will produce = 22.73 x 4 = 90.92 moles of H2O.

    Step 4:

    Determination of the volume of H2O. This is illustrated below:

    1 mole of a gas occupy 22.4L.

    Therefore, 90.92 moles of H2O will occupy = 90.92 x 22.4 = 2037 L.

    Therefore, 2037 L of water is boiled by burning 1kg of propane (C3H8)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How many liters of water can be boiled by burning 1 kg of propane? Round your answer to the nearest whole number. ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers