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13 May, 21:22

How many moles of gas are present in 1.13 L of gas at 2.09 atm and 291 K?

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Answers (1)
  1. 14 May, 00:26
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    n = 0.0989 moles

    Explanation:

    n = PV / RT

    P = 2.09atm

    V = 1.13L

    R = 0.08206

    T = 291K

    Plug the numbers in the equation.

    n = (2.09atm) (1.13L) / (0.08206) (291K)

    n = 0.0989 moles
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