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24 June, 05:20

What is the pressure of 0.540 mol of an ideal gas at 35.5 L and 223 K

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Answers (2)
  1. 24 June, 07:36
    0
    28.2 kPa on edge uwu
  2. 24 June, 08:36
    0
    0.0443 atm

    Explanation:

    1) dа ta:

    a) n = 0.540 mol

    b) V = 35.5 liter

    c) T = 223 K

    2) Formula:

    Ideal gas equation: PV = nRT

    Where,

    P = pressure V = volume n = number of moles T = absolute temperature (kelvin scale) R = universal gas constant = 0.08203 atm-liter/K-mol

    3) Calculations:

    Solve for P

    PV = nRT ⇒ P = nRT/V

    Substitute and compute:

    P = 0.540 mol * 0.08206 atm-liter/K-mol * 223 K / 35.5 liter

    P = 0.0443 atm (you must use 3 significant figures).
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