Be sure to answer all parts. Be sure to report your answer to the correct number of significant figures. Determine Kb of the weak base B whose conjugate acid HB + has Ka 6.6 * 10-4. * 10 Determine the Ka of the weak acid HA whose conjugate base has Kb 2.1 * 10-8.

part 1: Kb of the weak base = 1.5 x 10^-11

part 2: Ka of the weak acid = 4.8 x 10^-7

Explanation:

Using the formula Ka x Kb = 1.0 x 10^-14

Part 1:

Ka x Kb = 1.0 x 10^-14

Kb = (1.0 x 10^-14) / Ka = (1.0 x 10^-14) / (6.6 x 10^-4) = 1.5 x 10^-11

Part 2:

Ka x Kb = 1.0 x 10^-14

Ka = (1.0 x 10^-14) / Kb = (1.0 x 10^-14) / (2.1 x 10^-8) = 4.8 x 10^-7