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27 January, 13:19

What is the molarity of 15.0 g of NaBR in 0.250 L of solution

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  1. 27 January, 16:53
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    n = m/M = 15/102.894 = 0.1457811 moles

    c = n/V = n / 0.25 = 0.58312438 moles/dm3
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