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23 November, 15:01

A 3.2-l volume of neon gas (ne) is at a pressure of 3.3 atm and a temperature of 330 k. the atomic mass of neon is 20.2 g/mol, avogadro's number is 6.022 * 1023 molecules/mol, and the ideal gas constant is r = 8.314 j/mol · k = 0.0821 l · atm/mol · k. the mass of the neon gas is closest to

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  1. 23 November, 17:30
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    Answer is: the mass of the neon gas is closest to 7.8 grams.

    V (neon) = 3.2 L; volume.

    T = 330 K; temperature of gas.

    p = 3.3 atm; pressure of gas.

    R = 0.08206 L·atm/mol·K; gas constant.

    Ideal gas law: p·V = n·R·T.

    n = p·V / R·T.

    n (neon) = 3.3 atm · 3.2 L / 0.08206 L·atm/mol·K · 330 K.

    n (Ne) = 0.389 mol; amount of substance.

    m (Ne) = n (Ne) · M (Ne).

    m (Ne) = 0.389 mol · 20.2 g/mol.

    m (Ne) = 7.878 g; mass of neon.
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