Ask Question
9 January, 11:01

If you had excess aluminum, how many moles of aluminum chloride could be produced from 17.0 g of chlorine gas, cl2?

+4
Answers (1)
  1. 9 January, 13:47
    0
    The moles of aluminum chloride could be produced from 17.0g chloride gas is 0.159 moles

    calculation

    write the equation for formation of aluminum chloride

    that is 2Al + 3Cl2→ 2 AlCl3

    find the moles of Cl2 used

    moles = mass of Cl2 / molar mass of Cl2 (35.5 x2 = 71 g/mol)

    17g/71 g = 0.239 moles

    by use of mole ratio between Cl2 to AlCl3 which is 3:2 the moles of AlCl3 is therefore = 0.239 x2/3 = 0.159 moles
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “If you had excess aluminum, how many moles of aluminum chloride could be produced from 17.0 g of chlorine gas, cl2? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers