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21 April, 16:06

A 0.050L solution of Ba (OH) 2 is neutralized by 0.072L of a 0.55 M HNO3 solution. What is the concentration of the Ba (OH) 2 solution?

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  1. 21 April, 19:57
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    0.396M

    Explanation:

    Step 1:

    The balanced equation for the reaction. This is given below:

    2HNO3 + Ba (OH) 2 - > Ba (NO3) 2 + 2H2O

    From the balanced equation above,

    The mole ratio of the acid (nA) = 2

    The mole ratio of the base (nB) = 1

    Step 2:

    Data obtained from the question. This include the following:

    Volume of base (Vb) = 0.05L

    Concentration of base (Cb) = ... ?

    Volume of acid (Va) = 0.072L

    Concentration of acid = 0.55 M

    Step 3:

    Determination of the concentration of the base, Ba (OH) 2.

    The concentration of the base, Ba (OH) 2 can be obtained as follow:

    Cava / CbVb = nA/nB

    0.55 x 0.072 / Cb x 0.05 = 2/1

    Cross multiply to express in linear form

    Cb x 0.05 x 2 = 0.55 x 0.072

    Divide both side by 0.05 x 2

    Cb = (0.55 x 0.072) / (0.05 x 2)

    Cb = 0.396M

    Therefore, the concentration of the base, Ba (OH) 2 is 0.396M
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