Ask Question
29 May, 13:17

For the reaction A (g) → 2 B (g), K = 14.7 at 298 K. What is the value of Q for this reaction at 298 K when ∆G = - 20.5 kJ/mol?

+1
Answers (1)
  1. 29 May, 13:29
    0
    Q = 245 = 2.5 * 10^2

    Explanation:

    ΔG = ΔGº + RTLnQ, so also ΔGº = - RTLnK

    R = 8,314 J/molK, T=298K

    ΔGº = - RTLnK = - 6659.3 J/mol = - 6.7 KJ/mol

    ΔG = ΔGº + RTLnQ → - 20.5KJ/mol = - 6.7 KJ/mol + 2.5KJ/mol * LnQ

    → 5.5 = LnQ → Q = 245 = 2.5 * 10^2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “For the reaction A (g) → 2 B (g), K = 14.7 at 298 K. What is the value of Q for this reaction at 298 K when ∆G = - 20.5 kJ/mol? ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers