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1 December, 06:09

475 grams of solid calcium oxide reacts with water vapor to form solid calcium hydroxide. Calculate the heat of reaction.

(A) - 221.1 kcal

(B) + 290.8 kcal

C) - 290.8 kcal

(D) + 324.6 kcal

(E) + 221.1 kcal

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  1. 1 December, 06:22
    0
    (A) - 221.1 kcal

    Explanation:

    Based in the reaction:

    CaO (s) + H₂O (g) → Ca (OH) ₂ ΔH = - 109kJ/mol

    When 1 mole of CaO reacts per mole of water vapor producing calcium hydroxide there are released - 109kJ

    475g of CaO (Molar mass CaO: 56.08g/mol) are:

    475g CaO * (1mol / 56.08g) = 8.47 moles of CaO

    As 1 mole of CaO in reaction release - 109kJ, 8.47 moles release:

    8.47 mol CaO * (-109 kJ / 1 mol CaO) = - 923.2kJ are released

    As 1 kCal = 4.184kJ:

    -923.2kJ * (1kCal / 4.184kJ) =

    -220.7kCal ≈ (A) - 221.1 kcal
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