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25 November, 02:31

What would be the pH of a solution whose [OH-] is 2.8 * 10-5M?

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  1. 25 November, 03:53
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    pOH = - log [OH-]

    pOH=-log[2.8E-5]

    pOH = 4.55

    pOH + pH = 14

    pH = 14 - 4.55

    pH = 9.45

    SORRY IF THIS IS WRONG
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