Ask Question
21 September, 11:30

A solution of potassium cyanide, KCN, is made by dissolving 3.2 g of KCN in water. When this solution reacts with excess hydrochloric acid, HCl, it produces 0.30 g of poisonous hydrogen cyanide gas, HCN.

KCN + HCl - -> KCl + HCN

(a) Calculate the theoretical yield of HCN.

(b) Calculate the percent yield of HCN.

+5
Answers (2)
  1. 21 September, 11:49
    0
    The theoretical yield HCN is 1.33 grams

    The percent yield HCN is 22.56 %

    Explanation:

    Step 1: Data given

    Mass of KCN = 3.2 grams

    Molar mass KCN = 65.12 g/mol

    Mass of HCN produced = 0.30 grams

    Step 2: The balanced equation

    KCN + HCl - -> KCl + HCN

    Step 3: Calculate moles KCN

    Moles KCN = mass KCN / moalr mass KCN

    Moles KCN = 3.2 grams / 65.12 g/mol

    Moles KCN = 0.0491 moles

    Step 4: Calculate moles HCN

    For 1 mol KCN we need 1 mol HCl to produce 1 mol KCl and 1 mol HCN

    For 0.0491 moles HCN we'll have 0.0491 moles HCN

    Step 5: Calculate mass HCN

    Mass HCN = moles HCN * molar mass HCN

    Mass HCN = 0.0491 moles * 27.03 g/mol

    Mass HCN = 1.33 grams = the theoretical yield

    Step 6: Calculate the percent yield HCN

    Percent yield = (actual yiel / theoretical yield) * 100 %

    Percent yield = (0.30 grams / 1.33 grams)

    Percent yield = 22.56 %
  2. 21 September, 13:51
    0
    22.7%

    Explanation:

    We must first put down the equation of reaction to guide our work while solving the problem.

    KCN (aq) + HCl (aq) - -> KCl (aq) + HCN (aq)

    The questions specifically state that HCl is in excess so KCN is the limiting reactant.

    Number of moles of KCN reacted = mass of KCN reacted / molar mass of KCN

    Mass of KCN reacted = 3.2 g

    Molar mass of KCN = 65.12 g/mol

    Number of moles of KCN = 3.2/65.12 g/mol = 0.049 moles

    Theoretical yield of HCN is obtained thus;

    From the reaction equation;

    1 mol of KCN produced 1 mole of HCN thus 0.049 moles of KCN will produce 0.049 moles of HCN.

    Mass of HCN = number of moles * molar mass

    Molar mass of HCN = 27.0253 g/mol

    Hence mass of HCN produced = 0.049mol * 27.0253 g/mol = 1.32g of HCN

    Actual yield of HCN = 0.30g

    % yield = actual yield / theoretical yield * 100

    % yield = 0.30/1.32 * 100

    %yield = 22.7%
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A solution of potassium cyanide, KCN, is made by dissolving 3.2 g of KCN in water. When this solution reacts with excess hydrochloric acid, ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers